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3x^2-102x+819=0
a = 3; b = -102; c = +819;
Δ = b2-4ac
Δ = -1022-4·3·819
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-102)-24}{2*3}=\frac{78}{6} =13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-102)+24}{2*3}=\frac{126}{6} =21 $
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